[Dev-luatex] [luatex] lua module search behaviour

Taco Hoekwater taco at elvenkind.com
Sat Apr 13 12:13:04 CEST 2013


On 04/13/2013 10:03 AM, Élie Roux wrote:
> Dear all,
>
> I'm currently updating luatexbase, and I have a few questions:
>
> The first two are related to the behaviour when searching for
> "module.submodule" as "module/submodule.lua":
>
>   - Am I right if I say that package.searchers[2] looks weel for it but
>     kpse.find_file("module.submodule", 'lua') doesn't?

Yes. But package.searchers[2] is quite trivial. In lua code, it would
look like this:

function search (name)
    altname = string.gsub(file,'.','/')
    filename = kpse.find_file(altname, 'lua')	
    if not filename then
      filename = kpse.find_file(name, 'lua')
    end
    if not filename then
      return string.format("[kpse lua searcher] file not found: %s", name)
    else
      return loadfile(filename)
    end
end


>   - If it's true, is there a way to make it work with kpse.find_file?

Just write a thin wrapper to replace '.' with '/', as above.

> The goal of not just letting packages.searchers[2] do his job quietly
> (which it does well), is just to print the name of the loaded file,
> between brackets... So the third question is:
>    - is it possible to make the kpse version of packages.searchers[2]
>      return a string containing the file name?

That is not possible. It has to return either an error string, or a
loader function (the result of loadfile()).

Best wishes,
Taco



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