On Tue, 4 Sep 2012, Wolfgang Schuster wrote:

Am 04.09.2012 um 14:21 schrieb Marco Patzer :

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Hi,

I discovered strange behaviour concerning Lua conditionals within texdefinitions.

ConTeXt complains: 'then' expected near 'thenelseend'.

I guess it has something to do with how the content of a texdefinitions is grabbed. Seems like a bug or is this by design?

When you use the texdefinition environment to create a command the end of line character which results normally in a space is ignored sees “thenelseend” as a single string, in such a case you can add a space and put a comment sign at the end of the line.

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% This one fails % \starttexdefinition mycmd % \startluacode % if true then % else % end % \stopluacode % \stoptexdefinition

\starttexdefintion mycmd \startluacode if true then % else % end \stopluacode \stoptexdefinition

Why does adding semicolon not work? Aditya

On 2012-09-04 Wolfgang Schuster wrote:

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Why does adding semicolon not work?

Do you have a example?

\starttext \startluacode if true then; context("true") else; context("false") end \stopluacode \stoptext Marco

On 2012-09-04 Herbert Voss wrote: Hi Herbert,

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\starttext \startluacode if true then; context("true") else; context("false") end \stopluacode \stoptext

that is no Lua syntax

if true then; print("true") else; print("false") end This snippet fed into a standalone Lua interpreter prints “true” on the terminal. I admit, I did not look up the syntax in the manual, but I have in mind that semicolons can be used to separate statements that are on one line. Marco

Am 04.09.2012 21:05, schrieb Marco Patzer:

if true then; print("true") else; print("false") end

This snippet fed into a standalone Lua interpreter prints “true” on the terminal.

I admit, I did not look up the syntax in the manual, but I have in mind that semicolons can be used to separate statements that are on one line.

voss@shania:~/ConTeXt> lua zzz.lua lua: zzz.lua:1: unexpected symbol near ';' voss@shania:~/ConTeXt> lua -v Lua 5.1.4 Copyright (C) 1994-2008 Lua.org, PUC-Rio Herbert

Am 04.09.2012 21:35, schrieb Marco Patzer:

On 2012-09-04 Herbert Voss wrote:

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voss@shania:~/ConTeXt> lua zzz.lua lua: zzz.lua:1: unexpected symbol near ';'

marco@homerow:/tmp$ lua t.lua true

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voss@shania:~/ConTeXt> lua -v Lua 5.1.4 Copyright (C) 1994-2008 Lua.org, PUC-Rio

marco@homerow:/tmp$ lua -v Lua 5.2.1 Copyright (C) 1994-2012 Lua.org, PUC-Rio

the syntax changes, see http://www.lua.org/manual/5.2/manual.html#9 Herbert

On Tue, Sep 4, 2012 at 9:35 PM, Marco Patzer wrote:

On 2012-09-04 Herbert Voss wrote:

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voss@shania:~/ConTeXt> lua zzz.lua lua: zzz.lua:1: unexpected symbol near ';'

marco@homerow:/tmp$ lua t.lua true

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voss@shania:~/ConTeXt> lua -v Lua 5.1.4 Copyright (C) 1994-2008 Lua.org, PUC-Rio

marco@homerow:/tmp$ lua -v Lua 5.2.1 Copyright (C) 1994-2012 Lua.org, PUC-Rio

Because in Lua 5.2 there is the empty statements http://www.lua.org/manual/5.2/manual.html#3 """ 3.3.1 – Blocks A block is a list of statements, which are executed sequentially: block ::= {stat} Lua has empty statements that allow you to separate statements with semicolons, start a block with a semicolon or write two semicolons in sequence: stat ::= ‘;’ """ So stat ::= if exp then block {elseif exp then block} [else block] end means that if exp then ; else ; end is valid. Luatex still uses lua 5.1.4 -- luigi

On Tue, Sep 4, 2012 at 9:05 PM, Aditya Mahajan wrote:

On Tue, 4 Sep 2012, Herbert Voss wrote:

Am 04.09.2012 20:44, schrieb Marco Patzer:

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On 2012-09-04 Wolfgang Schuster wrote:

Why does adding semicolon not work?

...

...

Do you have a example?

\starttext \startluacode if true then; context("true") else; context("false") end \stopluacode \stoptext

that is no Lua syntax

I thought that semicolons were optional in lua are equal to end of lines.

Aditya

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http://www.lua.org/manual/5.1/manual.html#2.4.4 """ The unit of execution of Lua is called a chunk. A chunk is simply a sequence of statements, which are executed sequentially. Each statement can be optionally followed by a semicolon: : : 2.4.4 - Control Structures The control structures if, while, and repeat have the usual meaning and familiar syntax: stat ::= while exp do block end stat ::= repeat block until exp stat ::= if exp then block {elseif exp then block} [else block] end """ (as conseguence if exp then; block else; block end is not valid ) -- luigi

On 4-9-2012 20:44, Marco Patzer wrote:

On 2012-09-04 Wolfgang Schuster wrote:

...

...

Why does adding semicolon not work?

Do you have a example?

\starttext \startluacode if true then; context("true") else; context("false") end \stopluacode \stoptext

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