Equivalent for hdots and hdotsfor
In LaTeX, I can use \hdots for horizontal dots and \hdotsfor{n} to fill for several columns in a determinant. But these do not work in ConTeXt. What is the equivalent for these in ConTeXt? -- Respect, Shiv Shankar Dayal
Never mind, I found the solution on list that we can use \dotfill and \multispan{n}{\dotfill} as a substitute for what I have asked for. On Sat, Dec 30, 2023 at 2:11 PM Shiv Shankar Dayal < shivshankar.dayal@gmail.com> wrote:
In LaTeX, I can use \hdots for horizontal dots and \hdotsfor{n} to fill for several columns in a determinant. But these do not work in ConTeXt. What is the equivalent for these in ConTeXt?
-- Respect, Shiv Shankar Dayal
-- Respect, Shiv Shankar Dayal
Shiv Shankar Dayal schrieb am 30.12.2023 um 09:41:
In LaTeX, I can use \hdots for horizontal dots and \hdotsfor{n} to fill for several columns in a determinant. But these do not work in ConTeXt. What is the equivalent for these in ConTeXt?
Can you show the desired output from LaTeX with a PDF file and a minimal example of your ConTeXt version. Wolfgang
Hi,
On Sat, Dec 30, 2023 at 9:45 AM Shiv Shankar Dayal
In LaTeX, I can use \hdots for horizontal dots and \hdotsfor{n} to fill for several columns in a determinant. But these do not work in ConTeXt. What is the equivalent for these in ConTeXt?
You can try \HF or \HF[n]. \startTEXpage[offset=1DK] \dm{ \startnamedmatrix[matrix:bars] \NC 1 \NC x \NC x^2 \NC \ldots \NC x^{n-1} \NR \NC 1 \NC y \NC y^2 \NC \ldots \NC y^{n-1} \NR \HF[3] \NR \NC 1 \NC z \NC z^2 \NC \ldots \NC z^{n-1} \NR \stopnamedmatrix } \stopTEXpage /Mikael
participants (3)
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Mikael Sundqvist
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Shiv Shankar Dayal
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Wolfgang Schuster