I got it. Following works for me for last case: \item $a_1 = 7, d = 8. T_{n + 1} - T_n = a_n\forall n\geq 1$. $\startalign[n=3, location=packed] \NC S = \NC T_1 + \NC T_2 + T_3 + \cdots + T_n\NR \NC S = \NC \NC T_1 + T_2 + \cdots + T_{n - 1} + T_n\NR \stopalign$ On Tue, Jul 15, 2025 at 7:38 AM Shiv Shankar Dayal wrote:

Much appreciated for the help. It works nicely when this follows the \item immediately. However, if I use it after some text in \item it is aligned with list enumerator and does not indent. How can I achieve that?

On Tue, Jul 15, 2025 at 7:32 AM Aditya Mahajan wrote:

...

On Tue, 15 Jul 2025, Shiv Shankar Dayal wrote:

...

Consider following code:

\starttext \startitemize[n] \item \startformula \startalign[n=3] \NC S = \NC T_1 + \NC T_2 + T_3 + \cdots + T_n\NR \NC S = \NC \NC T_1 + T_2 + \cdots + T_{n - 1} + T_n\NR \stopalign\stopformula \stopitemize \stoptext

The formula is centered below the list enumerator and mid-aligned. How can I align it to left and in the same line as list enumerator. I tried replacing \startformula with $ but then it goes above the list enumerator and is still mid-aligned. I tried setting flushleft and align attributes but they did not work.

You need a couple of things:

- \startformula ... \stopformula uses the full local width. You need to use inline math $ ... $ (I use \startimath ... \stopimath below so that it looks nicer).

- You need to add location=packed to \startalign so that it does not use extra horizontal space

- Then you can adjust the vertical location by wrapping everything in a frame.

\starttext \startitemize[n] \item \startframed[align=normal,frame=off,location=high] \startimath \startalign[n=3,location=packed] \NC S = \NC T_1 + \NC T_2 + T_3 + \cdots + T_n\NR \NC S = \NC \NC T_1 + T_2 + \cdots + T_{n - 1} + T_n\NR \stopalign \stopimath \stopframed \stopitemize \stoptext

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-- Respect, Shiv Shankar Dayal

-- Respect, Shiv Shankar Dayal