Hi Wolfgang, Quoting Wolfgang Schuster :

Hi Aditya,

the macro eats the endline char.

That would mean that tex will parse ============= \section why \unknown test ============= as =============== \section why \unknown test ================ but it does not. What I dislike is the fact that TeX gives an error message. Aditya

On Wed, 11 Jul 2007, Wolfgang Schuster wrote:

2007/7/10, Aditya Mahajan :

...

Hi Wolfgang,

Quoting Wolfgang Schuster :

...

Hi Aditya,

the macro eats the endline char.

That would mean that tex will parse ============= \section why \unknown

test

=============

as

=============== \section why \unknown test

================

but it does not. What I dislike is the fact that TeX gives an error message.

Aditya

Hi Aditya,

the problem lies in the definition of \dowithpargument. The current defintion is:

\def\dowithpargument#1% {\def\nextpar##1 \par{#1{##1}}% \def\nextarg##1{#1{##1}}% \doifnextcharelse\bgroup\nextarg{\doifnextcharelse\par{#1{}}\nextpar}}

The problem is the space after ##1 in the \nexpar defintion, it should be:

\def\dowithpargument#1% {\def\nextpar##1\par{#1{##1}}% \def\nextarg##1{#1{##1}}% \doifnextcharelse\bgroup\nextarg{\doifnextcharelse\par{#1{}}\nextpar}}

and everything works fine.

Ah, thanks. Aditya