Hi, $\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression? Thanks, Xan PS: Please CCme
On 8/20/2014 9:38 AM, Xan wrote:
Hi,
$\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?
Can you be more explicit? I get the attached.
Thanks, Xan
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On Wed, 20 Aug 2014, Xan wrote:
On Wed, 20 Aug 2014 09:38:49 +0200 Xan
ha escrit: Hi,
$\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?
Thanks, Xan
Yes.
That is a very old version of ConTeXt that you are using: "ConTeXt - 2013.05.28 00:36". Have you tried with a more recent version? Aditya
On Wed, 20 Aug 2014, Aditya Mahajan wrote:
On Wed, 20 Aug 2014, Xan wrote:
On Wed, 20 Aug 2014 09:38:49 +0200 Xan
ha escrit: Hi,
$\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?
Thanks, Xan
Yes.
That is a very old version of ConTeXt that you are using: "ConTeXt - 2013.05.28 00:36". Have you tried with a more recent version?
(Untested): With the older version, you can try \overline instead of \overbar. Aditya
participants (3)
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Aditya Mahajan
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Hans Hagen
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Xan