Am Donnerstag, den 08.09.2011, 09:59 +0200 schrieb Wolfgang Schuster:

Am 08.09.2011 um 09:55 schrieb Aditya Mahajan:

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On Wed, 7 Sep 2011, Thomas Friedrich wrote:

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Hi,

I am having problems typing ">>" when typesetting code within a \definetyping environment.

I hope someone might be able to give me a hint. My code looks as follows:

\definetyping [Haskell] [ option=commands, before={\startframedtext[width=\makeupwidth, frame=off,bottomframe=on,topframe=on, background=screen,backgroundscreen=.90]}, after={\stopframedtext}, bodyfont=9pt, margin=1.5em]

\startHaskell main = foo >>= bar \stopHaskell

Whenever ConTeXt comes across >> anywhere in the text, it just doesn't typeset anything. So in the above case, I get the output:

main = foo = bar

Confirmed. >> are eaten in MkII but everything works fine with MkIV. My guess is because of automatic ligatures for >>. My usual trick for disabling such ligatures in MkII is

\usetypescript [modern] [texnansi] \setupbodyfont [modern]

but that does not work in this case. There were some discussions in the past about disabling ligatures in typewriter font, but I don't remember the exact solution.

No, the culprit is “option=commands" which gobbles “>>”.

Wolfgang

You are absolutely right, Wolfgang. When removing the "option=commands" from the definition, the ">>" won't get eaten. (Thanks!) However, my whole code consists of things such as \startHaskell main = f1 /BTEX$\circ$/ETEX f2 >>= hey \stopHaskell How comes that the ">>" are gobbled? Even worse, something like \startHaskell foo = bar =<< print \stopHaskell won't even compile. It doesn't like "<<". Question: Is there a way to replace the ">>" and "<<" strings in the typesetting environment by something else? Or another work around? Thanks, Thomas

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Am Donnerstag, den 08.09.2011, 10:57 +0200 schrieb luigi scarso:

On Thu, Sep 8, 2011 at 10:39 AM, Thomas Friedrich wrote:

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Question: Is there a way to replace the ">>" and "<<" strings in the typesetting environment by something else? Or another work around?

maybe \startHaskell foo = bar =/BTEX<

-- luigi

For anyone who's interested, I will do the following now: \startHaskell foo /BTEX{\tt >>\!=}/ETEX bar foo /BTEX>>\!=/ETEX bar bar /BTEX{\tt =\!<<}/ETEX foo bar /BTEX=\!<