(58 minus 6) times roman 'X'
It's DXX. Seriously, it's not a riddle, it's something you're supposed to type in when you want to make changes on the wiki without logging in as a registered user. It's supposed to save you the time and trouble of applying for an account, but obviously, if you need to ask the question on the list first it somehow fails its purpose.... Plus, there is a timeout on those things, I suppose, so you'd better hurry and type in the anwer ;-) Arthur
I don't know what is wrong, but I can't register to the wiki. It
always writes that "Login error: Incorrect or missing confirmation
code."
I wrote the answer to the question "(75 minus 5) times roman 'X' " as "DCC".
http://wiki.contextgarden.net/index.php?title=Special:UserLogin&type=signup&returnto=Main_Page
On Sat, Feb 20, 2010 at 12:52 PM, Arthur Reutenauer
(58 minus 6) times roman 'X'
It's DXX.
Seriously, it's not a riddle, it's something you're supposed to type in when you want to make changes on the wiki without logging in as a registered user. It's supposed to save you the time and trouble of applying for an account, but obviously, if you need to ask the question on the list first it somehow fails its purpose.... Plus, there is a timeout on those things, I suppose, so you'd better hurry and type in the anwer ;-)
Arthur ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki!
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I don't know what is wrong, but I can't register to the wiki. It always writes that "Login error: Incorrect or missing confirmation code."
I wrote the answer to the question "(75 minus 5) times roman 'X' " as "DCC".
On Sat, Feb 20, 2010 at 12:24 PM, Marius
There's alyaws "times roman something", where something corresponds to - I = 1 - X = 10 - C = 100 - M = 1000 So the "times" only tells you how many zeros to add to result. Mojca PS: Arthur will implement the parser to also accept roman numbers as a valid answer.
On Saturday 20 February 2010 15:07:31 Mojca Miklavec wrote:
There's alyaws "times roman something", where something corresponds to
- I = 1 - X = 10 - C = 100 - M = 1000
So the "times" only tells you how many zeros to add to result.
Mojca
PS: Arthur will implement the parser to also accept roman numbers as a valid answer.
(58 minus 6) times roman 'X'
= 01010 = 0x208 and it is also 580-60; the possibilities are truly endless... :)
(58 minus 6) times roman 'X'
= 01010 = 0x208
0b1000001000, mind you.
and it is also 580-60; the possibilities are truly endless... :)
We could write a parser that accepts any formula that yields the same result (including the result itself, in plain decimal notation), but the original one :-) Arthur
participants (5)
-
Alan BRASLAU -
Arthur Reutenauer -
luigi scarso -
Marius -
Mojca Miklavec