\sqrt[a]{b} with a more than one digit
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Hi, \sqrt[12]{a^{11}} produces me: \sqrt[1]{2} a^{11} What happens there? Xan.
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Try braces about the “12” as in
\sqrt{12}{a^{11}}
Alan
On Mon, Sep 23, 2013 at 3:55 AM, Xan
Hi,
\sqrt[12]{a^{11}}
produces me:
\sqrt[1]{2} a^{11}
What happens there?
Xan.
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Xan—I misunderstood. You are right. The latest beta does not allow
numerical roots higher than the 9th. Grouping the digits—as in
$\sqrt[{12}]{…}$ does not help.
Alan
On Mon, Sep 23, 2013 at 8:13 AM, Alan Bowen
Try braces about the “12” as in \sqrt{12}{a^{11}}
Alan
On Mon, Sep 23, 2013 at 3:55 AM, Xan
wrote: Hi,
\sqrt[12]{a^{11}}
produces me:
\sqrt[1]{2} a^{11}
What happens there?
Xan.
___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki!
maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net
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On 9/23/2013 5:43 PM, Alan Bowen wrote:
Xan—I misunderstood. You are right. The latest beta does not allow numerical roots higher than the 9th. Grouping the digits—as in $\sqrt[{12}]{…}$ does not help.
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participants (3)
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Alan Bowen
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Hans Hagen
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Xan