Hi John,
Wolfgang, thanks - but this does not seem to fix the problem. The "last page" appears opposite page 3 instead of opposite page 1.
To be clear, I am looking for a way to specify that content is to be placed on the outside of the cover, i.e. printed on the same side of the same sheet as page 1, when "arranged".
Could you try the following page brake method. \unprotect \installpagebreakhandler {newquadruple}% {\ifdoublesided \!!counta\realpageno \!!countb\realpageno \advance\!!counta 4 \divide\!!counta 4 \multiply\!!counta 4 \advance\!!countb 1 \advance\!!counta-\!!countb \executepagebreakhandler\v!yes \dorecurse\!!counta{\executepagebreakhandler\v!empty}% \fi} \protect
\setuppapersize[A5][A4] \setuparranging[2UP,rotated,doublesided] \setuppagenumbering[alternative=doublesided]
\setuplayout[margin=0pt,width=fit] \setupbodyfont[16pt]
\starttext
\dorecurse{11}{\input tufte \par \input knuth \par}
\page[8]
\page[8] is useless in this example because you're already beyound the eight page and the argument is useless in this case.
\page[quadruple]
\page[newquadruple]
Back Cover
\stoptext
texexec --arrange --paperformat=a5a4 --printformat=up test2.tex
texexec test2
you need --arrange only for documents with a table of content, indices ...
Wolfgang