11 Sep
2016
11 Sep
'16
8:48 p.m.
Just found that the code below does not work as intended, because \ππ’π¦ will be parsed as \π followed by π’π¦. Canβt tell if it ought to be changed, though one could think other cases where it might be natural. The command definition of \π works though. \setupbodyfont[xits,10pt] \setupmathematics[lcgreek=normal, default=normal] \definemathcommand[ππ’π¦][nolop]{\mfunction{ππ’π¦}} \definemathcommand[π][nolop]{\mfunction{ππ’π¦}} \starttext Note that $\ππ’π¦ π = π«$, although $\dim π = 4$. \stoptext