A partial answer: \definereferenceformat[infigure][text=Figure] \definereferenceformat[infigures][text=Figures] \definereferenceformat[intable][text=Table] \definereferenceformat[intables][text=Tables] \definereferenceformat[insection][text=Section] \definereferenceformat[inequation][left=(,right=),text=equation] \definereferenceformat[inexample][text=Example] \definereferenceformat[indefinition][text=Definition] Then, in \inequation[eq:newton], we see ... On Aug 4, 2006, at 5:44 PM, Renaud AUBIN wrote:
Hi all,
Is that possible to setup the \in command to obtain: - \in[fig:fig_ref] returns figure 1.1 - \in[eq:eq_ref] returns (1.1) _ \in[sec:sec_ref] returns section 2.1
Up to now I have used: - \in{figure}[fig:fig_ref] - \in{(}{)}[eq_eq_ref] (but there is an extra h space just after "(" ) - \in{section}[sec_sec_ref]
Moreover, how could I set the face of the output ?
Cheers,
Renaud _______________________________________________ ntg-context mailing list ntg-context@ntg.nl http://www.ntg.nl/mailman/listinfo/ntg-context