Re: [NTG-context] Bug in math alignment

Hi, On Wed, Nov 2, 2022 at 9:19 PM Otared Kavian via ntg-context wrote:

Dear Jeong,

Thanks for testing my example, and pointing to the solution using \dm (which I didn’t know…). I think the correct behaviour of math alignments should avoid using additional commands such as \dm.

We’ll see what Hans and Mikael say.

Best regards: OK

On 2 Nov 2022, at 12:53, Jeong Dal via ntg-context wrote:

Dear Otared,

I think there is an issue with the size of math fonts in \frac when used in math alignments, as it is is shown in the following example.

I confirm what you said.

However, if I use \dm{} instead of \displaystyle as following, then the output is correct.

\placeformula \startformula \startalignedcases \NC - \Delta u \NC = 0 \NC \qquad\text{in }\, \Omega \NR \NC \dm{\frac{\partial u}{\partial {\bi n}}} \NC = V u + \phi \NC \qquad\text{on }\, \partial\Omega. \NR \stopalignedcases \stopformula or this (with\type{\displaystyle} added) \placeformula \startformula \startalignedcases \NC - \Delta u \NC = 0 \NC \qquad\text{in }\, \Omega \NR \NC \dm{\frac{\partial u}{\partial {\bi n}}} \NC = V u + \phi \NC \qquad\text{on }\, \partial\Omega. \NR \stopalignedcases \stopformula

In this example, it is OK to use \dm inside of \startformula … \stopformula. I am not sure that it is what Hans and Mikael want.

Thanks,

Best regards,

Dalyoung

I think in this case it is better to use a mathsimplealign instead of a matrix. \definemathsimplealign[pdeproblem][ left={\startmathfenced[cases]}, right=\stopmathfenced, align={1:right,2:left,3:left}, strut=yes, ] \definemathsimplealign[collected][ left={\startmathfenced[sesac]}, right=\stopmathfenced, align={1:right,2:left,3:left}, strut=yes, ] \starttext \placeformula \startformula \startpdeproblem \NC - \Delta u \NC = 0 \NC \qquad\text{in } \Omega \NR \NC \frac{\partial u}{\partial {\bi n}} \NC = V u + \phi \NC \qquad\text{on } \partial\Omega \NR \stoppdeproblem \stopformula \placeformula \startformula \startcollected \NC - \Delta u \NC = 0 \NC \qquad\text{in } \Omega \NR \NC \frac{\partial u}{\partial {\bi n}} \NC = V u + \phi \NC \qquad\text{on } \partial\Omega \NR \stopcollected \stopformula \stoptext Best, Mikael