22 Sep
2010
22 Sep
'10
2:47 p.m.
On 22-9-2010 2:06, Otared Kavian wrote:
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\starttext Note that $\int_{0}^{2\pi} \sin(x)dx = 0$, while \startformula \int_{0}^{2\pi} \sin^2(x)dx = \pi \qquad \mbox{and}\qquad \sqrt{4}= 2. \stopformula \stoptext
Afaik nothing was changed so I'll wait for Taco's comments before I start messing around. Hans ----------------------------------------------------------------- Hans Hagen | PRAGMA ADE Ridderstraat 27 | 8061 GH Hasselt | The Netherlands tel: 038 477 53 69 | voip: 087 875 68 74 | www.pragma-ade.com | www.pragma-pod.nl -----------------------------------------------------------------