Here in Terminal on my Mac: 21 ~: lua Lua 5.4.6 Copyright (C) 1994-2023 Lua.org, PUC-Rio
string.gsub('a%20b', '%%20', ' ') a b 1 (string.gsub('a%20b', '%%20', ' ')) a b ^D 21 ~:
The first call returns the 1 giving the match, the extra ()'s get rid of that second return value. yours sincerely dr. Hans van der Meer
On 21 Jul 2023, at 12:37, denis.maier@unibe.ch wrote:
Hi,
I’m typesetting an XML document where the links to the images contain spaces which are encoded as %20 <graphic xlink:href="a%20filename%20with%20spaces.jpg"/>
Using this works in cases without spaces:
\startxmlsetups xml:fig:graphic \externalfigure[\xmlatt{#1}{xlink:href}] \stopxmlsetups
This also works for normal spaces, but is there a way to decode/expand the %20s to regular spaces?
I’ve tried with some Lua, but I don’t really know how to pass data around.
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \startluacode function replaceSpaces(s) result = string.gsub(s, "%%20", " ") context(result) end \stopluacode
\define[1]\replaceSpaces{\ctxlua{replaceSpaces("#1")}}
\startxmlsetups xml:fig:graphic \externalfigure[\replaceSpaces{\xmlatt{#1}{xlink:href}}] \stopxmlsetups %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Any hints, why this does not work?`
Also, maybe there’s a simpler way for this kind of scenario?
Best, Denis ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki!
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