On Di, 2011-05-24 at 09:56 -0400, Aditya Mahajan wrote:
On Tue, 24 May 2011, Paul Menzel wrote:
to markup the probability measure and the parenthesis around the argument, I defined the following command.
\define[1]\P{{\mathbf P}\left( #1 \right)}
Unfortunately the space between the P and the left ( is a little big in my opinion. Is that correct or should/can I fix that somehow?
Getting these spaces is tricky; especially if you consider spaces before and after the definition. Choose your pick:
\starttext \startformula A{\mathbf P}\left( ABC \right)B \quad A\mathop{\kern\zeropoint\mathbf P}\left( ABC \right)B \quad A{\mathbf P}\mathopen{}\left( ABC \right)\mathclose{}B \quad A\mathop{\kern\zeropoint\mathbf P}\mathopen{}\left( ABC \right)\mathclose{}B \quad \stopformula \stoptext
That looks tricky and complex.
Some information from the mathsets module (which does not work with MkIV).
I hope you or somebody will have time to port that module to MkIV.
The entry is the latex bug database is not viewable now.
%D The \type{\left} and \type{\right} generate a math atom of type inner, %D while for math sets, we want a math open atom. To see the difference, %D consider %D %D \startbuffer %D \startformula %D 2\left(\frac {3}{4} \right) \qquad \hbox{ vs } \qquad %D 2\biggl( \frac {3}{4} \biggr) %D \stopformula %D %D and %D %D \startformula %D \Pr\left(\frac {3}{4} \right) \qquad \hbox{ vs } \qquad %D \Pr\biggl( \frac {3}{4} \biggr) %D \stopformula %D \stopbuffer %D \typebuffer %D %D which gives (notice the spacing before the parenthesis) %D %D \getbuffer %D %D I will assume that if \type{text} is something, then %D the default behaviour is desirable, if \type{text} is empty, then I add %D \type{\mathopen} and \type{\mathclose}. Using \type{\mathopen} to correct %D the spacing is due to Frank Mittelbach, see %D \hyphenatedurl{http://www.latex-project.org/cgi-bin/ltxbugs2html?pr=latex/3853} %D %D Mathset module ensures that we get the correct spacing in both cases %D \startbuffer %D \definemathset[SET][left=(,right=)] %D \startformula %D 2\SET{\frac{3}{4}} \qquad \hbox{ and } \qquad %D \PR{ \frac{3}{4} } %D \stopformula %D \stopbuffer %D \getbuffer[PR] \getbuffer which was typed as \typebuffer %D %D Also, if its argument is a single character, \type{\mathop} centers it to %D with respect to the math||axis. Compare the outputs of %D %D \startbuffer %D \ruledhbox{$\mathop{y}\nolimits_x\left\{A\,\middle|\,B\right\}$} %D \ruledhbox{$\mathop{\kern\zeropoint y}\nolimits_x\left\{A\,\middle|\,B\right\}$} %D \stopbuffer %D %D \typebuffer %D \getbuffer %D %D I have added a \type{\kern\zeropoint} to prevent that.
Could you explain the advantage over `\!` which Wolfgang suggested at least for the space after the definition. In addition, I think AMSTeX defines a command `\DeclareMathOperator` [1] which takes care of these things. Thanks, Paul [1] http://en.wikibooks.org/wiki/LaTeX/Advanced_Mathematics#Custom_operators