On 15-7-2012 19:55, Peter Münster wrote:
Hi,
Is it possible to place one box beside another, both with the same height, one box with an image of unknown width, and the other uses the remaining width.
I've tried this, but without success:
--8<---------------cut here---------------start------------->8--- \starttext \bTABLE[offset=0pt, height=7cm, textwidth=\textwidth, option=stretch] \bTR \bTD bla bla bla bla bla bla bla bla bla \eTD \bTD \externalfigure[hacker][height=7cm] \eTD \eTR \eTABLE \stoptext --8<---------------cut here---------------end--------------->8---
If yes, how?
If no, then I'll try to get the width of the image with img.scan() ...
TIA for any hints!
\getfiguredimensions[hacker][height=7cm] \figurewidth \figureheight ----------------------------------------------------------------- Hans Hagen | PRAGMA ADE Ridderstraat 27 | 8061 GH Hasselt | The Netherlands tel: 038 477 53 69 | voip: 087 875 68 74 | www.pragma-ade.com | www.pragma-pod.nl -----------------------------------------------------------------