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2007/10/30, Wolfgang Werners-Lucchini
Sorry, I don't understand what the problem is!
It is related to ConTeXt's multicolumn Output Routine.
I have a problem with
\startitemize[columns,a] \item $a_n=2+\frac{1}{n+1}$ \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$ \stopitemize
Hi,
this did not wotk because the second formula is than the first and -------------------------------------------------^ (what?)
the multicolumn OTR tries to put half or less of the text into the second column, you can now force a second column with the \column command after the first line or you switch both formulas and the OTR can make two columns.
\starttext
\startitemize[columns,a] \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$ \item $a_n=2+\frac{1}{n+1}$ \stopitemize
Why is this working? Here the first column is as big as the second above (same formula), so the same problem should arise with the first column as above with the second?
No, they are not, the first row (column) is 1 points taller than the second one, you can test this with TeX. \starttext \setbox\scratchbox\hbox{$a_n=\frac{(-1)^n}{\sqrt{n}}-3$} Formula 1: \copy\scratchbox Height of formula 1: \the\ht\scratchbox \setbox\scratchbox\hbox{$a_n=2+\frac{1}{n+1}$} Formula 2: \copy\scratchbox Height of formula 2: \the\ht\scratchbox \stoptext
\startitemize[columns,a]
\item $a_n=2+\frac{1}{n+1}$ \column \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$ \stopitemize
Why does the \column help with the first formula?
Because itemize use for the columns key the multicolumns envrionment where you can force a new column with the \column command. The internal work for this case is something like in the following example: \starttext \startcolumns $a_n=\frac{(-1)^n}{\sqrt{n}}-3$ $a_n=2+\frac{1}{n+1}$ \stopcolumns \startcolumns $a_n=2+\frac{1}{n+1}$ \column $a_n=\frac{(-1)^n}{\sqrt{n}}-3$ \stopcolumns \stoptext No, I don't understand this at all. I hope my examples helped you a little bit to understand the problems in your example and why my methods worked. Wolfgang