![](https://secure.gravatar.com/avatar/5faea8b4fa0adb143383811dc94f0d22.jpg?s=120&d=mm&r=g)
Hi Fabrice, As Wolfgang points out, it is indeed possible to fill-in your table with Lua: maybe you were wondering how to fill the columns 2, 3 and 4. In this case you need to use the Lua function math.mod as in the following, which is a completed version of what Wolfgang sent: %% begin filling-with-lua.tex \starttext \startluacode context.startxtable{ align = "middle,lohi", bodyfont = "9pt", framecolor = "black" } context.startxrow{ background = "color", backgroundcolor = "lightgray" } context.startxcell{ nx = 4 } context("Units digit of") context.stopxcell() context.stopxrow() context.startxrow() context.startxcell{ width = "1cm" } context.im("a") context.stopxcell() context.startxcell{ width = "1cm" } context.im("a^2") context.stopxcell() context.startxcell{ width = "1cm" } context.im("b") context.stopxcell() context.startxcell{ width = "1cm" } context.im("2b^2") context.stopxcell() context.stopxrow() for i = 0,9 do context.startxrow() for j = 1,4 do context.startxcell() if j == 1 then context(i) elseif j == 2 then context(math.mod(i*i,10)) elseif j == 3 then context(i) else context(math.mod(2*i*i,10)) end context.stopxcell() end context.stopxrow() end context.stopxtable() \stopluacode \stoptext %% end filling-with-lua.tex Best regards: Otared
On 23 Aug 2023, at 17:48, Wolfgang Schuster
wrote: Fabrice Couvreur schrieb am 23.08.2023 um 19:28:
Hi, I'm trying to fill an array using lua. So far it works but then I don't know if it's possible.
Where do you have problems (look into cld-mkiv.pdf for hins)?
\starttext
\startluacode context.startxtable{ align = "middle,lohi", bodyfont = "9pt", framecolor = "black" } context.startxrow{ background = "color", backgroundcolor = "lightgray" } context.startxcell{ nx = 4 } context("Units digit of") context.stopxcell() context.stopxrow() context.startxrow() context.startxcell{ width = "1cm" } context.im("a") context.stopxcell() context.startxcell{ width = "1cm" } context.im("a^2") context.stopxcell() context.startxcell{ width = "1cm" } context.im("b") context.stopxcell() context.startxcell{ width = "1cm" } context.im("2b^2") context.stopxcell() context.stopxrow() for i = 0,9 do context.startxrow() for j = 1,4 do context.startxcell() if j == 1 then context(i) end context.stopxcell() end context.stopxrow() end context.stopxtable() \stopluacode
\stoptext
Wolfgang
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