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\starttext

Evaluate the following derivatives.

\startitemize[n, columns, two, nowhite, after]

\item\hspace[big] $\frac{d}{dx} x^2$

This is where the solution should be. Text answers look fine, but formulas have too much space above, below and between lines\dots.

\item\hspace[big] $\frac{d}{dx}\left( x^3 + 2x \right)$

\item\hspace[big] $\frac{d}{dx}\left( x^{-2} \right)$

\item\hspace[big] $\frac{d}{dt}\left( 4t^4 - 3t^{\onehalf} \right) $

\item\hspace[big] $\frac{d}{dt}( 9 - 3t )$

\startformula\startmathalignment
\NC \frac{d}{dt}( 9 - 3t ) \NC= \frac{d}{dt} 9 - \frac{d}{dt} 3t \NR
\NC  \NC= 0 - 3\frac{d}{dt} t \NR
\NC  \NC= -3\cdot 1t^0 \NR
\NC  \NC= -3 \NR
\stopmathalignment\stopformula

\item\hspace[big] $\frac{d}{dp}\left( p^3 - 2p \right)$

\stopitemize

Evaluate the following derivatives.

\startitemize[n]

\item\hspace[big] $\frac{d}{dx} x^2$

This is where the solution should be. Text answers look fine, and formulas look good, too\dots.

\item\hspace[big] $\frac{d}{dt}( 9 - 3t )$

\startformula\startmathalignment
\NC \frac{d}{dt}( 9 - 3t ) \NC= \frac{d}{dt} 9 - \frac{d}{dt} 3t \NR
\NC  \NC= 0 - 3\frac{d}{dt} t \NR
\NC  \NC= -3\cdot 1t^0 \NR
\NC  \NC= -3 \NR
\stopmathalignment\stopformula

\item\hspace[big] $\frac{d}{dp}\left( p^3 - 2p \right)$

\stopitemize
\stoptext

