Hi Fabrice,

Do you know the step charts module in ConTeXt? I guess you can achieve what you want as in the example below (sorry, I did not took your example, I am just copying an example from my archives…).

%%%%%%%%%%
\usemodule[steps]
\starttext

Pour voir que la composée de deux fonctions $f$ et $u$, continues en un point $x_{*}$, est continue, on peut suivre le schéma suivant~:
\placefigure[middle,none][-]{}{
%\scale[,width=.35\textwidth]{
\startSTEPtable 
\cell {$(f\circ u)(x_{*} + o(1)) = $} \text{définition de $f\circ u$}
\cell {$f\left(u\left(x_{*} + o(1)\right)\right) = $} \text {$u$ est continue} 
\cell {$f\left(u(x_{*}) + o(1)\right) = $} \text {$f$ est continue} 
\cell {$f\left(u(x_{*})\right) + o(1) =$} \text {définition de $f\circ u$} 
\cell {$(f\circ u)(x_{*}) + o(1)$.} 
\stopSTEPtable
%}
}
\stoptext
%%%%%%%%%%

Best regrads: Otared



On 25 Jul 2016, at 10:36, Fabrice Couvreur <fabrice1.couvreur@gmail.com> wrote:

Hello,
My way is not very elegant but I would do this:

Formula
                   arrow text
Formula
                   arrow text
Formula
                   arrow text
Formula

#########################################################
\startuseMPgraphic{MyArrow}
path p ;
p:=(0,0){right}..(0.5cm,-0.6cm)..(0,-1.2cm){left} ;
drawarrow p withpen pencircle scaled 1.5bp withcolor 0.625white ;
\stopuseMPgraphic

\starttext

\showgrid

\math{A\times X=B}
 
\hfill On multiplie, à gauche, les deux membres de l'égalité par \math{A^{-1}}.

\hskip 5cm \relax \dontleavehmode\useMPgraphic{MyArrow}

\math{A^{-1}\times A\times X=A^{-1}\times B}

\hfill On utilise l'égalité \math{A^{-1}\times A=I}.

\hskip 5cm \relax \dontleavehmode \useMPgraphic{MyArrow}

\math{I\times X=A^{-1}\times B}

\hfill On utilise l'égalité \math{X\times I=I\times X=X}.

\hskip 5cm \relax \dontleavehmode \useMPgraphic{MyArrow}

On a donc \math{X=A^{-1}\times B}  
 
\stoptext
#########################################################

Thanks,
Fabrice
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