Hello there and thanks for finally let me into this mailing list! So I tried to hack the macro given in the ConTeXt wiki (http://wiki.contextgarden.net/Page_numbering_in_words) to write pagenumbering in words in spanish, my native language. Things were great until I had to reach the 100th page. ConTeXt claims when compiling, but I don't know how to fix the macro so it can write hundred-numbers. 'Cien' is 100 for spanish. 'Ciento uno' for 101, 'ciento dos' for 102 and so (You can see a more detailed example in http://spanish.about.com/cs/forbeginners/a/cardinalnum_beg.htm). So basically I need to prepend the word 'cien' for each word number from 1 to 99 to write the one-hundreds, 'doscientos' for the two-hundreds... Here is my dirty hacked version of the macro (you may save it as 'numstr.tex' for compiling), and a minimal example as follows: \input numstr \defineconversion[numstring][\numstr] \setupuserpagenumber[numberconversion=numstring] \starttext \dorecurse{100}{\recurselevel\page} \stoptext I'm such a noob with TeX and I cannot figure out how to do this, and I need this for this friday!. However, Aditya in the TeX section of StackExchange (http://tex.stackexchange.com/questions/82722/context-page-numbering-in-words... for-spanish#comment178155_82722) told me that I could do this witk Lua (editing the file core-con.lua, as seen in http://repo.or.cz/w/context.git/blob/HEAD:/tex/context/base/core-con.lua ), 'cause I'm using MkIV for doing this. But I don't know anything about Lua (seems pretty easy, but I don't know how to test the code Aditya gave me) and If I knew how to do that, I don't know how to make it work in my document... All I could do is translate the 'words' array to spanish, but I couldn't do more... Could you guys give me a hand on this? Thank you so much!