Hi,
I want to simulate \hss in lua end in ConTeXt/luametatex environment. For example,
```ConTeXt a{\raise 1.5ex\hbox to 0pt{\hss b}}c ```
And in lua, I do as follows(part of my app seen in attachment):
Your code doesn't compile as is. I think that this is the same thing though: \starttext \startluacode local a = node.new"glyph" a.char = string.byte("a") a.font = font.current() local b = node.new"glyph" b.char = string.byte("b") b.font = font.current() local c = node.new"glyph" c.char = string.byte("c") c.font = font.current() local hss = node.new("glue") hss.stretch = 65536 hss.stretchorder = 2 hss.shrink = 65536 hss.shrinkorder = 2 hss.width = 0 b = node.insertbefore(b, b, hss) local box = node.new("hlist", "box") box.head = b box.width = 0 box.shift = -tex.sp("1ex") tex.forcehmode() node.write(a + box + c) \stopluacode \stoptext
And got 'b' on top of 'c' in pdf as follows:
```pdf b ac ```
The \hss isn't the problem here. The problem is actually with the box. When you manually make the \hbox like that, I think (although I could be wrong) that you're bypassing all of TeX's glue calculations. You should probably use "node.hpack" instead: \starttext \startluacode local a = node.new"glyph" a.char = string.byte("a") a.font = font.current() local b = node.new"glyph" b.char = string.byte("b") b.font = font.current() local c = node.new"glyph" c.char = string.byte("c") c.font = font.current() local hss = node.new("glue") hss.stretch = 65536 hss.stretchorder = 2 hss.shrink = 65536 hss.shrinkorder = 2 hss.width = 0 local box = node.hpack(hss + b, "exactly", 0) box.shift = -tex.sp("1ex") tex.forcehmode() a.next = box box.next = c node.write(a) \stopluacode \stoptext -- Max