[NTG-context] Re: equation to right margin

9 Oct 2024

      Thank you, Mikael. That is very helpful and much appreciated.

What I now have is:
\startplaceformula
  \startformula
    \startalign
      \NC \[21-(9 - n^2)\NC =□^\prime\]  \NR[eq:1]
      \NC  n^2+12 \NC=□^\prime.          \NR[eq:2]
    \stopalign
  \stopformula
\stopplaceformula
which put the numbers at the right margin,as I wanted.

So how do I get a brace on the left rather than on the right?  Or is there
documentation that explains this?

Alan

On Wed, Oct 9, 2024 at 10:22 AM Mikael Sundqvist  wrote:
...
Hi,
On Mon, Oct 7, 2024 at 11:45 PM Alan Bowen  wrote:
...
I have the following which works, except for the fact that the equation
number does not go to the right margin.
...
\startplaceformula
\startformula[align=middle, prefix=no]
\startcases[distance=2pt]
\NC \[21-(9 - n^2)\NC =□^\prime\]\NR
\NC\hfill n^2+12 \NC=□^\prime.\NR[eq04]
\stopcases
\stopformula
\stopplaceformula
I expect that I have missed something pretty basic here, so any guidance
will be greatly appreciated.
Maybe I misunderstand you, but I do not think cases is right here.
Also, are you sure you want to group two equations but only number one
of them.
If I understand you correctly, I'd try with one of these, depending on
if citing the group or one of the equations.
\starttext
\startformula
  \startalign[location=packed,fences=sesac]
    \NC \[21-(9 - n^2)\NC =□^\prime\]\NR
    \NC  n^2+12 \NC=□^\prime.        \NR
  \stopalign
  \numberhere[eq:foo]
\stopformula
\startplaceformula
  \startformula
    \startalign
      \NC \[21-(9 - n^2)\NC =□^\prime\]  \NR%[eq:bar-a]
      \NC  n^2+12 \NC=□^\prime.          \NR[eq:bar-b]
    \stopalign
  \stopformula
\stopplaceformula
\stoptext
/Mikael
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