It works nicely. You are a lifesaver. Thanks a lot.
On Mon, Jan 15, 2024 at 7:30 PM Mikael Sundqvist
Hi,
you can try something like
\sum_{\mstack{k=0, k\equiv p + 1 (\mtext{mod }2)}}^{p -1}
but it will not be too pretty with such a large sub-index to the sum.
/Mikael
On Mon, Jan 15, 2024 at 2:41 PM Shiv Shankar Dayal
wrote: I have following formula \sum_{k=0\\ k\equiv p + 1(\mathrm{mod}\;2)}^{p -1} but the \\ does not
break the line below Sigma. How can I achieve this because AFAIK it will work in LaTeX?
-- Respect, Shiv Shankar Dayal
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___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki!
maillist : ntg-context@ntg.nl / https://mailman.ntg.nl/mailman3/lists/ntg-context.ntg.nl webpage : https://www.pragma-ade.nl / https://context.aanhet.net (mirror) archive : https://github.com/contextgarden/context wiki : https://wiki.contextgarden.net
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-- Respect, Shiv Shankar Dayal