<--- On Mar 27, Taco Hoekwater wrote --->
Hi,
Aditya Mahajan wrote:
This seems to be working fine. However, \intertext defined in amsmath.sty seems to be doing a lot more (I just can't figure out what it is doing?) Can someone suggest how to make the above command more robust on the lines of \intertext?
It inserts a post/pre-display skip&penalty pair around the intertext, then creates a \vbox for use a paragraph. The result is (almost) as if it the text was part of the 'normal' text flow between two displays.
I cannot tell you if this would work exactly the same as expected in ConTeXt (needs further testing), but a context-like solution would look like this:
\def\startintertext#1\stopintertext{% \noalign{\dointertext{#1}}\NR}
\unexpanded\def\dointertext#1% {\penalty\postdisplaypenalty \afterdisplayspace % the matching \before... is not needed \vbox{\forgetall \noindent #1\par}% \penalty\postdisplaypenalty }
This does not look good. Consider, \def\startintertext#1\stopintertext{% \noalign{\dointertext{#1}}\NR} \unexpanded\def\dointertext#1% {\penalty\postdisplaypenalty \afterdisplayspace % the matching \before... is not needed \vbox{\forgetall \noindent #1\par}% \penalty\postdisplaypenalty } \startformula \startalign \NC A_1 \NC= \left| \int_0^1 (x^2 - 3x)\, dx \right| + \left| \int_1^2 (x^2 -5x + 6)\, dx \right| \NR \startintertext Take limits of both integrals \stopintertext \NC \NC = \left| \frac{x^3}{3} - \frac{3}{2} x^2 \right|_0^1 + \left| \frac {x ^3}{3} - 7 \frac{5}{2} x^2 + 6x \right|_1^2 \NR \NC \NC = \left| - \frac{7}{6} \right| + \left|\frac{14}{3} - \frac{23}{6}\right| = \frac{7}{6} + \frac{5}{6} = 2 \NR \stopalign \stopformula There is too much space after the intertext and the next line. Can you provide some magic to reduce this space. Thanks, Aditya -- Aditya Mahajan, EECS Systems, University of Michigan http://www.eecs.umich.edu/~adityam || Ph: 7342624008