Hi Fabrice, I think you have to use \startalign[n=3,align={left,right}] and finish the alignment with \stopalign Is this what you are looking for? \starttext \startformula \startalign[n=3,align={left,right}] \NC \qquad \NC\frac{\lvert\overline{AD}\rvert}{\lvert\overline{CD}\rvert} \NC =\frac{\lvert\overline{DC}\rvert}{\lvert\overline{CE'}\rvert}\NR \NC \iff \NC \frac{1}{x} \NC =\frac{x}{1-x} \NR \NC \iff \NC 1-x \NC =x^2 \NR \NC \iff \NC 0\NC =x^2+x-1 \NR \stopalign \stopformula \stoptext Best regards: OK
On 5 Jan 2019, at 12:27, Fabrice Couvreur
wrote: Hi, I'm trying to get the same result for this file compiled with latex. Thanks. Fabrice
\documentclass{article} \usepackage{amsmath}
\begin{document}
\begin{alignat*}{2} &\qquad&
\frac{\lvert\overline{AD}\rvert}{\lvert\overline{CD}\rvert}
&=\frac{\lvert\overline{DC}\rvert}{\lvert\overline{CE'}\rvert}\\ \iff&& \frac{1}{x}&=\frac{x}{1-x}\\ \iff&& 1-x&=x^2\\ \iff&& 0&= x^2+x-1
\end{alignat*}
\end{document}
\starttext \startformula \startmathalignment[n=3] \NC \qquad \NC\frac{\lvert\overline{AD}\rvert}{\lvert\overline{CD}\rvert} \NC =\frac{\lvert\overline{DC}\rvert}{\lvert\overline{CE'}\rvert}\NR \NC \iff \NC \frac{1}{x} \NC =\frac{x}{1-x} \NR \NC \iff \NC 1-x \NC =x² \NR \NC \iff \NC 0\NC =x²+x-1 \NR \stopmathalignment \stopformula \stoptext
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