Dear Peter, thank you for your answer. Am Freitag, den 21.10.2011, 17:02 +0200 schrieb Peter Rolf:
I agree, this is confusing on the first sight. But scaling is not meant as 'scaling to' a dimension. In fact is is just a simple multiplication. The reason why it seems to work this way with 'fullsquare' and such predefined paths is, that they have a 'neutral' size/scale (bounding box size of filled path is (1pt,1pt)).
So how can I find out what the dimension of the path of a function is? Not scaling it, it also looked pretty small, so I am guessing (1pt,1pt).
Multiplying such a path with (x,y) gives an object with size (1*x,1*y). In general: if the bounding box of an object has the size (a,b) and you scale it with (x,y), the resulting object has a size of (ax,by). That's all the magic.
but if you use numbers with a unit than it should not be multiplied but expanded to that value, should not it? Otherwise I am unsure how multiplication works with a unit.
I must admit that this wasn't clear to me before you came up with your question. So thanks for that. :-)
Thank you for your answer. As written above it is still not entirely clear to me. I hope you can remedy my last confusion. Thanks a lot, Paul