Am 10.06.2009 um 11:47 schrieb Nicolas Girard:
* If so, I don't understand how can \dosetuparrangement{3}{1}{6}{4}{2} give 1|2|3 // 4|5|6 . What's the rationale ? Why no page 5 among the arguments of \dosetuparrangement ?
The placement of the pages is defined \pusharrangedpageTHREESIDE, the values above mean: • number of columns: 3 • number of rows: 1 • total number of pages: 6 (ConTeXt collects 6 pages and arrange them before they are written to the pdf file but in Willi's code 3 had been enough) • number of crop marks in x direction: 4 (columns + 1) • number of crop mark in y direction: 2 (rows + 1)
* What if one wants to fold the resulting brochure ? How to adapt the code (besides by try and error) for the resulting arrangement to be 3|6|1 // 2|4|5 ?
The page order in a brochure is 5|6|1 and 2|3|4. Wolfgang