Hi, In setting out to update our intermediate algebra textbook for the fall semester (http://msenux.redwoods.edu/IntAlgText/), I've found that a file that would formerly compile under a previous version of context will no longer compile. Preliminaries $ ctxtools --contextversion CtxTools | context version: 2007.06.06 09:53 (/usr/local/gwTeX/ texmf.local/tex/context/base/context.tex) CtxTools | context version: 2007.06.06 09:53 (/usr/local/gwTeX/ texmf.local/tex/context/base/cont-new.tex) Preliminaries $ texmfstart texexec --version TeXExec | version 6.2.0 - 1997-2006 - PRAGMA ADE/POD The error message I receive is: textblocks : reading blocks from NumberSystemsExercises.tub (./NumberSystemsExercises.tub textblocks : shortanswer loaded and typeset textblocks : shortanswer loaded and processed textblocks : shortanswer loaded and typeset textblocks : shortanswer loaded and processed textblocks : shortanswer loaded and typeset textblocks : shortanswer loaded and processed textblocks : shortanswer loaded and typeset textblocks : shortanswer loaded and processed textblocks : shortanswer loaded and typeset ! Missing number, treated as zero. <to be read again> \relax \dogenfrac ...{\begingroup #4\endgroup #2#3\relax #5}} \mathematics #1->\relax \ifmmode #1 \else $#1$\fi l.216 $ \frac{81}{125} $ ? The point in the source that seems to cause the difficulty is: \noindent In \in{Exercises}[ex:secqu.9]-\in[ex:secqu.16], convert the given decimal to a fraction. % Exercise #9 \beginquestion \startquestion[ex:secqu.9] $0.648$ \stopquestion \endquestion \beginlonganswer \startanswer There are three decimal places, so $0.648=\frac{648}{1000}=\frac{81}{125}$. \stopanswer \endlonganswer \beginshortanswer \startanswer $\displaystyle \frac{81}{125}$ \stopanswer \endshortanswer Shortanswer and longanswer are blocks. Startanswer is an enumeration. I've tried this in other files and gotten similar errors, which seem to be tied to the frac command. Can anyone help?