Thanks, Aditya, I have adapted this as follows— \startbuffer \item item 1 \startitemize[n,stopper={},width=1em] \item item 1.1 \item item 1.2 \item item 1.3 \stopitemize \item item 2 \startitemize[n,stopper={},width=1em] \item item 2.1 \item item 2.2 \item item 2.3 \stopitemize \item item 3 \startitemize[n,stopper={},width=1em] \item item 3.1 \item item 3.2 \stopitemize \stopbuffer % \setupitemize[n,serried,packed,joinedup] \startitemize[repeat]\getbuffer\stopitemize and everything works, except that I cannot seems get the subitems indented. Right now they fall directly beneath the main items. All best, Alan On Sep 30, 2007, at 12:28 PM, Aditya Mahajan wrote:
On Sun, 30 Sep 2007, Alan Bowen wrote:
I need to produce an lengthy itemization of the form: 1.AAAA 1.1 aaaa 1.2 bbbb 2.BBBB 2.1 cccc
I can get: 1.AAAA 1 aaaa 2 bbbb 2.BBBB 1 cccc easily enough, but how can I get the main division number to repeat in the subitem numeration?
From core-itm.tex
% \startbuffer % \item % \startitemize[n] % \item item 1.1 % \item item 1.2 % \startitemize[n] \item item 1.2.1 \item item 1.2.2 \stopitemize % \item item 1.3 % \stopitemize % \item % \startitemize[n] \item item 2.1 \item item 2.2 \stopitemize % \item item 3 % \startitemize[n] \item item 3.1 \item item 3.2 \stopitemize % \item % \startitemize[n] \item item 4.1 \item item 4.2 \stopitemize % \stopbuffer % % \startitemize[n,repeat,6*broad,packed] \getbuffer \stopitemize \blank[3*big] % \startitemize[n,repeat,packed] \getbuffer \stopitemize \blank[3*big] % \setupitemize[each][atmargin][width=3em] % \startitemize[n,repeat,packed] \getbuffer \stopitemize
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