Re: [NTG-context] Problem with string.format (Lua)

14 Jan 2018


      Hi Hans,
Your code runs perfectly, thanks. However, if I replace % with
\letterpercent, my code does not run

\ctxlua{print(string.format("\letterpercent g",Binomial(100,60,0.25)))}

Thank you
Fabrice

2018-01-14 13:58 GMT+01:00 Hans Hagen :
...
On 1/14/2018 1:13 PM, Joseph Canedo wrote:
...
Hi Fabrice,
string.format behaves more or less as C printf. You probably need to
specify %.4g in 1st argument.
Hope this helps
Best
Joseph
*De : *Fabrice Couvreur mailto:fabrice1.couvreur@gmail.com
*Envoyé le :*dimanche 14 janvier 2018 13:05
*À : *mailing list for ConTeXt users mailto:ntg-context@ntg.nl
*Objet :*[NTG-context] Problem with string.format (Lua)
Hello,
I start with Lua and I try to display my result with 4 decimal places
without success.
Thank you
Fabrice
\startluacode
function Binomial(n,k,p)
     if k > n then return nil end
     if k > n/2 then k = n - k end
numer, denom = 1, 1
     for i = 1, k do
         numer = numer * ( n - i + 1 )
         denom = denom * i
     end
     return (numer/denom) * p^k * (1-p)^(n-k)
end
\stopluacode
\starttext
\ctxlua{print(string.format("%g",Binomial(100,60,0.25)))}
\stoptext
the % should be \letterpercent
btw, use locals for numer and denom
you can also do this:
\startluacode
    function document.Binomial(n,k,p)
        if k > n then
            return nil
        end
        if k > n/2 then
            k = n - k
        end
        local numer, denom = 1, 1
        for i=1,k do
            numer = numer * ( n - i + 1 )
            denom = denom * i
        end
        context("%0.5g",(numer/denom) * p^k * (1-p)^(n-k))
    end
\stopluacode
\starttext
    \ctxlua{document.Binomial(100,60,0.25)}
\stoptext
in general
context("format",....)
is a bit more powerful than using format
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