Outside math I think the solution is \inframed, but I don't know if
that works here.
Johan
2006/1/14, David Arnold
All,
I have:
\placeformula[-] \startformula \eqalign{ &\text{Divisors of 12}: \framed{1},\ \framed{2},\ \framed{3},\ 4,\ \framed{6},\ 12\cr &\text{Divisors of 18}: \framed{1},\ \framed{2},\ \framed{3},\ \framed{6},\ 9,\ 18} \stopformula
But I'd like to keep the numbers on the same baseline and let the frame dip below the baseline. _______________________________________________ ntg-context mailing list ntg-context@ntg.nl http://www.ntg.nl/mailman/listinfo/ntg-context
-- Johan Sandblom N8, MRC, Karolinska sjh t +46851776108 17176 Stockholm m +46735521477 Sweden "What is wanted is not the will to believe, but the will to find out, which is the exact opposite" - Bertrand Russell