Hi,
on a 64 bit Windows machine os.uname() erroneously returns
machine i686
On the same machine I get under Linux
machine x86_64
with both, x86_64-linux and i386-linux binaries. Thus I assume that
the keyword 'machine' refers to the hardware, not to how the binaries
were compiled (32 vs. 64 bit).
The complete output of
for k,v in pairs(os.uname()) do
print(k,v)
end
is
release build 9200
nodename R804
version 6.02
machine i686
sysname Windows 8
#ifdef _WIN32
# define _UTSNAME_LENGTH 65
/* Structure describing the system and machine. */
struct utsname {
char sysname[_UTSNAME_LENGTH];
char nodename[_UTSNAME_LENGTH];
char release[_UTSNAME_LENGTH];
char version[_UTSNAME_LENGTH];
char machine[_UTSNAME_LENGTH];
};
/*
* Get name and information about current kernel.
*/
static int uname(struct utsname *uts)
:
case WinNT:
sprintf(uts->machine, "i%d86", sysinfo.wProcessorLevel);
break;
I guess that wProcessorLevel gives 6 in your case.
--
luigi